independent

Independent events

Two events $A$ and $B$ are independent if knowing $A$ gives no extra information about $B$, and vice versa:

$$\begin{array}{r}P(A\mid B)=P(A)\\ P(B\mid A)=P(B)\end{array}$$

Equivalently, using the formula of conditional probability, we can say:

$$\begin{array}{rl}P(A)& =P(A\mid B)=\frac{P(A\cap B)}{P(B)}\\ P(A\cap B)& =P(A)\cdot P(B)\end{array}$$

EXAMPLE

$\Omega$ = deck of 52 cards
$A$ = card is spade → $P(A)=\frac{1}{4}$
$B$ = card is queen → $P(B)=\frac{1}{13}$
$P(A\cap B)=P(A)P(B)=\frac{1}{52}$
The probability of getting a spade or queen doesn’t change if we restrict ourselves to the set $A$ or $B$: